From a solid wooden cube of sides $14 c m$ a biggest hemispherical depression is carved out. What is the total surface area of the remain solid?

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Solution

$\begin{matrix} T o t a l s u r f a c e a r e a o f r e m a i n i n g s o l i d = 6 a^{2} - π r^{2} + 2 π r^{2} = 6 a^{2} + π r^{2} = 6 {(14)}^{2} + \frac{22}{7} \times 7 \times 7 = 6 \times 196 + 154 = 1330 c m^{2} \end{matrix}$

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From a solid wooden cube of sides 14 cm a biggest hemispherical depression is carved out. What is the total surface area of the remain solid?

Totalsurfaceareaofremainingsolid=6a2−πr2+2πr2=6a2+πr2=6(14)2+227×7×7=6×196+154=1330cm2

From a solid wooden cube of sides $14 c m$ a biggest hemispherical depression is carved out. What is the total surface area of the remain solid?

$\begin{matrix} T o t a l s u r f a c e a r e a o f r e m a i n i n g s o l i d = 6 a^{2} - π r^{2} + 2 π r^{2} = 6 a^{2} + π r^{2} = 6 {(14)}^{2} + \frac{22}{7} \times 7 \times 7 = 6 \times 196 + 154 = 1330 c m^{2} \end{matrix}$