If the initial disc had a mass
M, The cutout part would have a man
m2=M/4 (assuming man is uniforming distributed)
The center of mass of initial disc,
→r1=O^i+O^j and that of cutout disc
→r2=(R2^i+O^j) [from fig.]
Thus, COM of remaining part,
→r=m1→r1−m2→r2m1−m2=M(O^i+O^j)−M4(R2^i+O^j)M−M4
=−MR8^i+O^j3m4=(−R6^i+O^j)
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