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Question

From a uniform disc of radius R, a small disc of radius R2 has been cut out from the left having centre at (R2,0) and is placed on the right with centre at (R2,0) as shown in the figure. Find the centre of mass of the resulting system.


A
xcom=R2
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B
xcom=R4
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C
ycom=0
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D
ycom=R2
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Solution

The correct options are
B xcom=R4
C ycom=0

Let M be the total mass of disc.
Mass of the cut out portion (m),
m=MπR2.π(R2)2
m=M4

After the smaller disc has been cut from the original and is placed on the right of the centre of the disc, the remaining portion is considered to be a system of three masses.
The three masses are:
M concentrated at (0,0),
m(=M/4) concentrated at (R2,0) and
m(=M/4) concentrated at (R2,0)

COM of the new system:
xcom=Mx1mx2+mx3Mm+m[ x1=0, x2=R2, x3=R2]
xcom=M(0)M4(R2)+M4(R2)M=R4,ycom=0 [by symmetry]

Thus, option (b) and (c) are the correct answers.

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