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Question

From a uniform disc of radius R, a small disc of radius R2 is cut and removed as shown in the diagram. Find the center of mass of the remaining portion of the disc.
1030758_a06e40ef0ef948d6a038a6c5073c825b.png

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Solution

let the com of the original disebe at the origin
Bow let the com of small disc lie to the right
com of disc =at its centre
com =R2 of small disc
let the com of large disc be situated at ccm then com of large disc x
Now area of entire sheet πR2;mass/area=mπR2

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