From a water fall, water is falling at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100m then the power delivered to the turbine is approximately equal to

100kW

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10 kW

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1kW

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1000kW

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Solution

The correct option is A
100kW

$P o w e r = \frac{W o r k d o n e}{t} = \frac{m g h}{t} = 100 \times 10 \times 100 = 10^{5} w a t t = 100 k W [A s \frac{m}{t} = 100 \frac{k g}{s e c} (g i v e n)]$

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From a water fall, water is falling at the rate of 100 kg/s on the blades of turbine. If the height of the fall is 100m then the power delivered to the turbine is approximately equal to

The correct option is A 100kW Power=Work donet=mght=100×10×100=105 watt=100kW [As mt=100 kgsec(given)]

The correct option is A
100kW

$P o w e r = \frac{W o r k d o n e}{t} = \frac{m g h}{t} = 100 \times 10 \times 100 = 10^{5} w a t t = 100 k W [A s \frac{m}{t} = 100 \frac{k g}{s e c} (g i v e n)]$