From a waterfall, water pours down at the rate of $100 k g s^{- 1}$ on the blades of a turbine. If the height of the fall is 120 m, calculate the power delivered to the turbine?
(Given $g = 10 m s^{- 2}$ )

120 kW

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125 kW

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1200 W

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120 W

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Solution

The correct option is A
120 kW

Given:
Mass m = 100 kg,
Time t= 1 sec,
Height h= 120 m and
Acceleration due to gravity $g = 10 m s^{- 2}$ .
$Power = \frac{m g h}{t} = 100 \times 10 \times 120$
$∴ \frac{100 \times 10 \times 120}{1 s}$
Power = 120,000 watts = 120 kW

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From a waterfall, water pours down at the rate of 100 kgs−1 on the blades of a turbine. If the height of the fall is 120 m, calculate the power delivered to the turbine? (Given g=10 ms−2)

The correct option is A 120 kW Given: Mass m = 100 kg, Time t= 1 sec, Height h= 120 m and Acceleration due to gravity g=10 ms−2. Power=mght=100×10×120 ∴ 100×10×1201s Power = 120,000 watts = 120 kW

From a waterfall, water pours down at the rate of $100 k g s^{- 1}$ on the blades of a turbine. If the height of the fall is 120 m, calculate the power delivered to the turbine?
(Given $g = 10 m s^{- 2}$ )

The correct option is A
120 kW

Given:
Mass m = 100 kg,
Time t= 1 sec,
Height h= 120 m and
Acceleration due to gravity $g = 10 m s^{- 2}$ .
$Power = \frac{m g h}{t} = 100 \times 10 \times 120$
$∴ \frac{100 \times 10 \times 120}{1 s}$
Power = 120,000 watts = 120 kW