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Question

From a window (h metres high above the ground) of a house in a street, the angles of elevation and depression of the top and the foot of another house on the opposite side of the street are θ and ϕ respectively. Find the height of the opposite house.


A

h(1+cosec θ cot ϕ) metres

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B

h(1+sec θ cot ϕ) metres

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C

h(1+cot θ cot ϕ) metres

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D

h(1+tan θ cot ϕ) metres

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Solution

The correct option is D

h(1+tan θ cot ϕ) metres


Let AB be the house with window at B and let CD be the another house. Then, AB = h metres.



Draw BEAC, meeting CD at E. Then,

EBD=θ and ACB=EBC=ϕ

Let CD = H metres. Then,

CE = AB = h metres and

ED = CD - CE

ED = (H - h) m

From right ΔACB, we have

ACAB=cot ϕACh=cot ϕ

AC=h cot ϕ metres

From right ΔBED, we have

DEBE=tan θ(Hh)h cot ϕ=tan θ [BE=AC=h cot ϕ m]

(Hh)=h tan θ cot ϕ

H=h(1+tan θ cot ϕ)

Hence, the height of the opposite house is h(1+tan θ cot ϕ) metres.


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