From a window (h metres high above the ground) of a house in a street, the angles of elevation and depression of the top and the foot of another house on the opposite side of the street are θ and ϕ respectively. Find the height of the opposite house.
h(1+tan θ cot ϕ) metres
Let AB be the house with window at B and let CD be the another house. Then, AB = h metres.
Draw BE∥AC, meeting CD at E. Then,
∠EBD=θ and ∠ACB=∠EBC=ϕ
Let CD = H metres. Then,
CE = AB = h metres and
ED = CD - CE
ED = (H - h) m
From right ΔACB, we have
ACAB=cot ϕ⇒ACh=cot ϕ
⇒AC=h cot ϕ metres
From right ΔBED, we have
DEBE=tan θ⇒(H−h)h cot ϕ=tan θ [∵BE=AC=h cot ϕ m]
⇒(H−h)=h tan θ cot ϕ
⇒H=h(1+tan θ cot ϕ)
Hence, the height of the opposite house is h(1+tan θ cot ϕ) metres.