From an elevated point A a stone is projected verticalyy upwards. When the stone reaches a distance h below A its velocity is double of what it was at a height above A. The greatest height attained by the stone is nh/3. What is the value of n?
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Solution
Given : Distance=h Initial velocity of stone =u
Velocity at point B , "h" above A is : Vb²=u²-2gh Vb=√(u2-2gh)