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Question

From an elevated point P, a stone is projected vertically upwards. When it reaches a distance d below P, its velocity is doubled. The greatest height reached by it above P is :

A
d/3
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B
3d
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C
2d
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D
d/2
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Solution

The correct option is B d/3
vu=gt
2uu=gt
t=ug where, t is the time to go from u (downward) to 2u (downward).
ttotal=2ug+ug=3ug since ug is time to go up and same time to come down.
(2u)2u2=2gd
d=3u22g
Maximum height, H=u22g=d3

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