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# From each of the two opposite corners of a square of side 8 cm, a quadrant of a circle of radius 1.4 cm is cut. Another circle of radius 4.2 cm is also cut from the centre as shown in the following figure. Find the area of the remaining (Shaded) portion of the square. (Use π = 22/7) Open in App
Solution

## It is given that a circle of radius 4.2 cm and two quadrants of radius 1.4 cm are cut from a square of side 8 cm. Let the side of square be a. Then, Since the radius of circle is 4.2 cm. So, $Areaofcircle={\mathrm{\pi r}}^{2}\phantom{\rule{0ex}{0ex}}=\frac{22}{7}×4.2×4.2\phantom{\rule{0ex}{0ex}}=55.44{\mathrm{cm}}^{2}$ Now area of quadrant of circle of radius 1.4 cm is, $\mathrm{Area}\mathrm{of}\mathrm{shaded}\mathrm{region}=\mathrm{Area}\mathrm{of}\mathrm{square}-\mathrm{Area}\mathrm{of}\mathrm{circle}-2×\mathrm{Area}\mathrm{of}\mathrm{quadrant}\phantom{\rule{0ex}{0ex}}=64-55.44-2×1.54\phantom{\rule{0ex}{0ex}}=5.48{\mathrm{cm}}^{2}$  Suggest Corrections  2      Related Videos   Area of a Sector
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