Question

From Electronic configuration from $1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^1$ to $1s^{2}2s^{2}2p^{6}3s^{2}3p^{5}4s^2$ an electron would:

• A. Absorb energy
• B. Emit energy
• C. Relax to the ground state
• D. Bind to another atom
• E. Undergo no change in energy

Answer 1

The correct option is A Absorb energy

When the electron is moved from 3p subshell to 4s an electron move to the excited state by absorption of energy.

Electrons orbit the nucleus in seven distinct regions called energy levels.

When the atom is in the ground state, the electron is as close to the nucleus as it can get (the first energy level, n = 1) and an electron has the least amount of energy possible for an electron.

When the atom absorbs energy the electron can jump up to a higher energy level (n = 2, or n = 3) When this happens we say the atom is in an excited state.

Hence, the correct option is $\text{A}$