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Stoichiometric Calculations

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Question

from equation ,N2+3H2=2NH3 calculate the volume of ammonia gas formed when 6 litres of hydrogen react with excess nitrogen all volumes being at STP.

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Solution

$N_{2} + 3 H_{2} \to 2 N H_{3} T h e e q u a t i o n t e l l s t h a t 3 m o l e s o f H_{2} g i v e s 2 m o l e s o f a m m o n i a . i . e ., 3 \times 22.4 L o f H_{2} g i v e s 2 \times 22.4 L o f a m m o n i a . (\sin c e 1 m o l e o f a n y g a s o c c u p i e s 22.4 L v o l u m e) 6 L o f h y d r o g e n w i l l p r o d u c e = \frac{2 \times 22.4}{3 \times 22.4} \times 6 = 4 L o f a m m o n i a$

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Q. Nitrogen reacts with hydrogen to give ammonia. Calculate the volume of the ammonia gas formed when nitrogen reacts with 6 litres of hydrogen. All volumes measured at S.T.P.

Q. Ammonia gas is formed by the combination of nitrogen and hydrogen.

N_{2} + 3 H_{2} \to 2 N H_{3}

In the above equation :

Q. When 4 L of nitrogen completely reacts with hydrogen, what would be the volume of ammonia gas formed?

Q. Calculate the volume of ammonia gas produced at STP when 140 g of nitrogen gas reacts with 30 g hydrogen gas.

N = 14 u, H = 1 u

N_{2} + 3 H_{2} \to 2 {N H}_{3}

15 L

hydrogen is available for the reaction above, what volume of

{N H}_{3}

will be formed?
Assume an excess of nitrogen for this reaction and STP conditions.

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