From equations of motion, $v^{2} - u^{2} =$ ....................... .

2 gh

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\sqrt{2 h / g}

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2 as

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Zero

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Solution

The correct option is C 2 as
As we know that from third equations of motion
$v^{2}$ - $u^{2} = 2 a s$
where a is the acceleration of the body
s is the displacement of the body
u is the initial velocity of the body and
v is the final velocity of the body

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Similar questions

(v^{2} - u^{2} = 2 a s)

(v = u + a t

s = u t + \frac{1}{2} a t^{2})

Derive the following equation of motion by the graphical method :

$v^{2} = u^{2} + 2 a$

where the symbols have their usual meanings.

v^{2} = u^{2} + 2 a s

\to v,

h

\begin{matrix} Column-I & Column-II (a) The speed of body at any time t is & (p) \sqrt{\frac{2 g h}{u^{2}}} (b) It will strike the ground after time t is equal to & (q) \sqrt{\frac{2 h}{g}} (c) The path followed by the body is expressed as y equal to & (r) \frac{1}{2} g \frac{x^{2}}{u^{2}} (d) The value of tan θ, where θ is the angle made by velocity striking the ground with horizontal is equal to & (s) \sqrt{v^{2} + g^{2} t^{2}} \end{matrix}

v^{2}

u^{2}

a s

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