From four corners of a rectangular iron sheet of $24$ cm $\times 30$ cm, four squares of side $6$ cm are cut. The remaining portion of the sheet is formed into an open box. The internal volume (in cm $^{3}$ ) of the box is

4300

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2590

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2542

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1296

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Solution

The correct option is D $1296$
The base of the box (shaded portion in the diagram) has dimensions $(24 - 2 \times 6)$ by $(30 - 2 \times 6),$
i.e. $12$ cm $\times 18$ cm.
Height of the box $= 6$ cm
$∴$ Volume of the box $= 12 \times 18 \times 6 = 1296 c m^{3}$

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From four corners of a rectangular iron sheet of 24 cm ×30 cm, four squares of side 6 cm are cut. The remaining portion of the sheet is formed into an open box. The internal volume (in cm3) of the box is

The correct option is D 1296The base of the box (shaded portion in the diagram) has dimensions (24−2×6) by (30−2×6),i.e. 12 cm ×18 cm.Height of the box=6 cm∴ Volume of the box =12×18×6=1296cm3

From four corners of a rectangular iron sheet of $24$ cm $\times 30$ cm, four squares of side $6$ cm are cut. The remaining portion of the sheet is formed into an open box. The internal volume (in cm $^{3}$ ) of the box is

The correct option is D $1296$
The base of the box (shaded portion in the diagram) has dimensions $(24 - 2 \times 6)$ by $(30 - 2 \times 6),$
i.e. $12$ cm $\times 18$ cm.
Height of the box $= 6$ cm
$∴$ Volume of the box $= 12 \times 18 \times 6 = 1296 c m^{3}$