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From P(4, 0), tangents PA and PA are drawn to a circle, x2+y2=4. Where A and A is point of contact and A lies above x-axis. Rhombus PAPA is completed.

Column-IColumn-IIColumn-III(I)A(1,3)(i)PA=23(P)P lies on the circle, x2+y2=4(II)A(1,3)(ii)Area of ΔPAA=33 sq.units(Q)ΔPAA is equilateral(III)P=(4,0)(iii)PP=6(R)P lies outside the circle , x2+y2=4(IV)P=(2,0)(iv)Area of ΔPAA=43 sq.units(S)P lies inside circle , x2+y2=4

Which one of the following is correct?


A

(IV) (iii) S

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B

(IV) (ii) R

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C

(II) (ii) Q

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D

(III) (iv) P

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Solution

The correct option is C

(II) (ii) Q


PAA is an equilateral triangle with side length =23 square units.

So, area of the triangle PAA=34×23×23=33 square units.


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