From $P$ a line parallel to $y$ -axis is drawn and from $Q$ a line parallel to $x$ -axis is drawn. Both these lines intersect at the point $R$ . If the coordinates of $P$ and $Q$ are $(3, 4)$ and $(1, - 7)$ , then find the coordinates of $R$ .

(3, 7)

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(3, - 7)

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(1, - 4)

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(1, 4)

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Solution

The correct option is B $(3, - 7)$
The point $P = (p, q) = (3, 4)$ and a line is drawn parallel to $Y$ -axis.
Therefore, th equation of the line is $x = p = 3$
Again another line is drawn parallel to $X$ -axis through a point $Q = (r, s) = (1, - 7)$
Therefore, the equation of the line is $y = s = - 7$
Therefore, the lines are $x = 3$ and $y = - 7$
Therefore, the point of intersection is
$(x, y) = (3, - 7)$

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