Question

From the above figure, calculate the length of $AG$, if point $G$ is the center of rectangle $BCEF$.

• A. $\sqrt{10}$
• B. $\sqrt{13}$
• C. $\sqrt{85}$
• D. $\sqrt{97}$
• E. $11$

Answer 1

Answer: (C)

$\sqrt{85}$

$G$ will be the midpoint of $BE$.

Hence, $G=\frac{6+12}{2},\frac{4+0}{2}=9,2$
Hence, $AG=\sqrt{(9-0{)}^2+(2-0{)}^2}$

$=\sqrt{81+4}$

$=\sqrt{85}$