Question

From the adjoining figure find $x$, i $AOB$ is a straight line. Hence complete the following
Which is an acute angle?

Answer 1

R.E.F image

now ,we know

$\angle POA+\angle POB={180}^{\circ }$

$x+10+x-10={180}^{\circ }$

$2x={180}^{\circ }$

$[x={90}^{\circ }]$

NOW $\angle POB=90+10=80$

& $\angle POA=90+10={100}^{\circ }$

$\angle$ POB is acute angle.