From the centre of the earth to the surface of the earth, the relation between the value of g and distance (r) represented as a proportionality, is given by

g \propto \frac{1}{r^{2}}

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g \propto r

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g \propto r^{2}

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g \propto r^{o}

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Solution

The correct option is B $g \propto r$
The variation of g with the depth(r) $= g_{r} = \frac{G M}{R^{2}} (1 - \frac{r}{R})$

$\Rightarrow g_{r}$ $α$ $r$

Hence correct answer is option $B$

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From the centre of the earth to the surface of the earth, the relation between the value of g and distance (r) represented as a proportionality, is given by

The correct option is B g∝rThe variation of g with the depth(r) =gr=GMR2(1−rR)⇒gr α r Hence correct answer is option B

The correct option is B $g \propto r$
The variation of g with the depth(r) $= g_{r} = \frac{G M}{R^{2}} (1 - \frac{r}{R})$

$\Rightarrow g_{r}$ $α$ $r$

Hence correct answer is option $B$