Question

From the chart of the periodic table given, answer the following questions

$1$ lithium	$2$	$13$	$14$ Carbon	$15$	$16$ Oxygen	$17$	$18$ neon
$X$			$S$		$P$	$L$
$Y$						$Q$
$Z$						$R$
						$T$

Write the chemical formula of the compound formed between $Y$ and $P$ and state the nature of the bond.

Answer 1

The Resultant Chemical formula will be $Y_{2}P$ because $Y$ is under lithium group where valence electron is $1$ & P is under oxygen group where valence electron is 2

$Y$ $P$

$1$ $2$

so formula of the compound is $Y_{2}P$. The compound will have ionic bond.