From the choices given below, choose the equation whose graph is given fig:
From the choices given below, choose the equation whose graph is given fig:
The correct option is D y = – x + 2
Given: (-1, 3) and (2, 0) are the solution of one of the following given equations.
Check which equation satisfy both the points.
(i) y = x + 2
Putting, x = -1 and y = 3
3 ≠ – 1 + 2
L.H.S ≠ R.H.S
Putting, x = 2 and y = 0
0 ≠ 4
L.H.S ≠ R.H.S
Thus, this solution does not satisfy the given equation.
(ii) y = x – 2
Putting, x = -1 and y = 3
3 ≠ – 1 – 2
L.H.S ≠ R.H.S
Putting, x = 2 and y = 0
0 = 0
L.H.S = R.H.S
Thus, the given solutions does not satisfy this equation completely.
(iii) y = – x + 2
Putting, x = – 1 and y = 3
3 = – ( – 1 ) + 2
L.H.S = R.H.S
Putting x = 2 and y = 0
0 = -2 + 2
0 = 0
L.H.S = R.H.S
Therefore, (0, 2) and (-1,3) satisfy this equation.
Hence, this is the graph for equation y = -x + 2 .
(iv) x + 2y = 6
Putting, x = – 1 and y = 3
-1 + 2(3) = 6
-1 + 6 = 6
5 = 6
L.H.S ≠ R.H.S
Putting x = 2 and y = 0
2 + 2(0) = 6
2 = 6
L.H.S ≠ R.H.S
Thus, this solution does not satisfy the given equation.
Given: (-1, 3) and (2, 0) are the solution of one of the following given equations.
Check which equation satisfy both the points.
(i) y = x + 2
Putting, x = -1 and y = 3
3 ≠ – 1 + 2
L.H.S ≠ R.H.S
Putting, x = 2 and y = 0
0 ≠ 4
L.H.S ≠ R.H.S
Thus, this solution does not satisfy the given equation.
(ii) y = x – 2
Putting, x = -1 and y = 3
3 ≠ – 1 – 2
L.H.S ≠ R.H.S
Putting, x = 2 and y = 0
0 = 0
L.H.S = R.H.S
Thus, the given solutions does not satisfy this equation completely.
(iii) y = – x + 2
Putting, x = – 1 and y = 3
3 = – ( – 1 ) + 2
L.H.S = R.H.S
Putting x = 2 and y = 0
0 = -2 + 2
0 = 0
L.H.S = R.H.S
Therefore, (0, 2) and (-1,3) satisfy this equation.
Hence, this is the graph for equation y = -x + 2 .
(iv) x + 2y = 6
Putting, x = – 1 and y = 3
-1 + 2(3) = 6
-1 + 6 = 6
5 = 6
L.H.S ≠ R.H.S
Putting x = 2 and y = 0
2 + 2(0) = 6
2 = 6
L.H.S ≠ R.H.S
Thus, this solution does not satisfy the given equation.
