Question

From the consecutive integers -10 to 10, inclusive, 20 integers are randomly chosen with repetitions allowed. What is the least possible value of the product of the 20 integers?

• A. ${(-10)}^{20}$
• B. ${(-10)}^{10}$
• C. $0$
• D. ${-\left(10\right)}^{19}$
• E. ${-\left(10\right)}^{20}$

Answer 1

The correct option is E ${-\left(10\right)}^{20}$

For least value we take$10;19$ times $-10$ once

So value ${10}^{19}\times -10$

$=(-10{)}^{20}$

Hence the answer is $(-10{)}^{20}.$