Question

From the electrochemical series, it can be concluded that.

• A. $Z{n}^{2+}$ will liberate $H_2$ from $1MHCl$
• B. $Ag$ metal reacts spontaneously with $Z{n}^{2+}$
• C. $Zn$ metal will liberate $H_2$ from $1MHCl$
• D. $Ag$ metal will liberate $H_2$ from $1MHCl$

Answer 1

The correct option is C $Zn$ metal will liberate $H_2$ from $1MHCl$

As $Zn$ is placed above Hydrogen so $Zn$ has higher tendency to undergo oxidation than hydrogen and liberate $H_2$ from $HCl$.