From the equation $(x + 6) (x - 2) (x + 3) = 0$ , find the least value of $x$ .

x = - 6

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x = 2

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x = - 3

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x = 6

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Solution

The correct option is A $x = - 6$
Given, $(x + 6) (x - 2) (x + 3) = 0$
Apply zero property rule, we get
$x + 6 = 0, x - 2 = 0, x + 3 = 0$
$x = - 6, x = 2, x = - 3$
The least value of $x = - 6$

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