Question

From the figure, the angle of depression of point C from the point P is :

• A. ${90}^{\circ }$
• B. ${60}^{\circ }$
• C. ${30}^{\circ }$
• D. ${45}^{\circ }$

Answer 1

The correct option is C ${30}^{\circ }$

in $△PAB$

$\angle APB+{90}^o+{60}^o={180}^o\Rightarrow \angle APB={30}^o$

Now, $\angle APC=\angle APB+\angle BPC={30}^o+{30}^o={60}^o$

Now, in $△PAC$

${90}^o+{60}^o+\angle PCA={180}^o\Rightarrow \angle PCA={30}^o$

Therefore, Answer is $\angle PCA={30}^o$