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Byju's Answer
Standard XII
Chemistry
Rate Constant
From the foll...
Question

From the following data answer the questions:
Reaction: A + B → P

[A]M[B]MInitial rateM sec−1
300 K400 K
2.5×10−43.0×10−55.0×10−42.0×10−3
5.0×10−46.0×10−54.0×10−3
1.0×10−36.0×10−51.6×10−2

The order w.r.t A is:

A
1
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B
2
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C
3
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D
-1
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Solution

The correct option is A 2
The rate law expression is R=k[A]m[B]n
For experiment (1), 5×10−4=k[2.5×10−4]m[3×10−5]n

For experiment (2), 4×10−3=k[5×10−4]m[6×10−5]n......(1)

For experiment (3) 1.6×10−2=k[1×10−3]m[6×10−5]n......(2)

Divide equation (2) with equation (1)
1.6×10−24×10−3=k[1×10−3]m[6×10−5]nk[5×10−4]m[6×10−5]n
Hence, m=2

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Q.
From the following data answer the questions:
Reaction: A+B → P

[A] M[B] MInitial rateM sec−1
300 K400 K
2.5×10−43.0×10−55.0×10−42.0×10−3
5.0×10−46.0×10−54.0×10−3
1.0×10−36.0×10−51.6×10−2
The value of rate constant at 300 K is (m−2sec−1)
Q.
From the following data answer the questions:
Reaction: A+B → P

[A]M[B]MInitial rateM sec−1
300 K400 K
2.5×10−43.0×10−55.0×10−42.0×10−3
5.0×10−46.0×10−54.0×10−3
1.0×10−36.0×10−51.6×10−2
The energy of activation for reaction (kJ/mol) is:
Q. Following data are given for the reaction between A and B.
[A]/mol L−1[B]/mol L−1Initial rate/ mol L−1s−1 at
300 K		320 K
2.5×10−43.0×10−55.0×10−42.0×10−3
5.0×10−46.0×10−54.0×10−3-
1.0×10−36.0×10−51.6×10−2-
The rate constant at 300 K is:
Q.
Expt.
No.		 [A]
(molL−1)		 [B]
(molL−1) 		Initial rate (molL−1s−1)
300K 320K
(1) 2.5×10−4 3.0×10−5 5.0×10−4 2.0×10−3
(2) 5.0×10−4 6.0×10−5 4.0×10−3...
(3) 1.0×10−3 6.0×10−5 1.6×10−2...
From the data given above for the reaction between A and B, calculate the following:
(i) The order of the reaction with respect to A and with respect to B,
(ii) The rate constant at 300 K
(iii) The energy of activation and
(iv) The pre-exponential factor.
Q. From the given table for reaction between A and B:
Initial rateInitial rate [A] mol litre−1[B] mol litre−1at 300 Kat 320 K mol litre−1 s−1 mol litre−1 s−1(I) 2.5×10−43.0×10−55.0×10−42.0×10−3(II)5.0×10−46.0×10−54.0×10−3−(III) 1.0×10−36.0×10−51.6×10−2−

Rate constant at 300 K is x×108 mol−2 litre2 s−1. Find the value of x.
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