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Question

From the following data, calculate the enthalpy change for the combustion of cyclopropane at 298 K. The enthalpy of formation of CO2(g), H2O(l) and propane (g) are -393.5, -285.8 & 20.42 kJ/mol respectively. The enthalpy of isomerisation of cyclopropane to propene is -33.0 kJ/mol.

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Solution

We are give:
(i) C(s)+O2(g)CO2(g)ΔH=393.5 kJ mol1
(ii) H2(g)+12O2(g)H2O(l)ΔH=285.8 kJ mol1
(iii) 3C(s)+3H2(g)C3H6(g)ΔH=+20.42 kJ mol1
Operating (iv)-(iii)+3×(i)+3×(ii), we get the required equation and
ΔH=3320.42+3(393.5)+3(285.8)
=2091.32 kJ mol1

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