Question

From the following data of $\Delta H$, of the following reaction,
$C_{(}s)+\frac{1}{2}{O}_2(g)\to CO(g)$ $\Delta H=-110kJ$
$C\left(s\right)+H_{2}O\left(g\right)\to CO\left(g\right)+H_2\left(g\right)$ $\Delta =132kJ$
What is the mole composition of the mixture of steam and oxygen on being passed over coke 1273 K, keeping temperature constant?

• A. 0.5 : 1
• B. 0.6 : 1
• C. 0.8 : 1
• D. 1 : 1

Answer 1

The correct option is B 0.6 : 1

$C_{(}s)+\frac{1}{2}{O}_2(g)\to CO(g)$ $\Delta H=-110kJ$

$\downarrow$

Exothermic $B{x}^n$

$C\left(s\right)+H_{2}O\left(g\right)\to CO\left(g\right)+H_2\left(g\right)$ $\Delta =132kJ$

$\downarrow$

Endothermic $r{x}^n$

Total $\delta$ Evolved I = Total $\Delta$ evolved in II

$n_1\times 110=n_2\times 132\times 1$

$\therefore \frac{n_1}{n_2}=\frac{132}{110\times 2}=\frac{0.6}{1}$

$n_1$ = Moles of $O_2$ dusing $r{x}^n$

$n_2$ = moles of $H_{2}O$ dusing $r{x}^n$

$=0.6m$