From the following data of - H- of the following reaction- Cs-1-2O2g- COg- - H-110 kJ Cs-H2Og- COg-H2g- - H-132 kJWhat is the mole composition of the mixture of oxygen and steam on being passed over coke at 1273K- to keep temperature constant -

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Hess' Law

From the foll...

Question

From the following data of $Δ H$ , of the following reaction,
$C (s) + \frac{1}{2} O_{2} (g) \to C O (g);$ $Δ H = - 110 k J$
$C (s) + H_{2} O (g) \to C O (g) + H_{2} (g);$ $Δ H = 132 k J$
What is the mole composition of the mixture of oxygen and steam on being passed over coke at 1273K, to keep temperature constant ?

0.5 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.6 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.8 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

Δ H

C (s) + \frac{1}{2} O_{2} (g) \to C O (g)

Δ H = - 110 k J

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g)

Δ H = 132 k J

Δ H

C_{(} s) + \frac{1}{2} O_{2} (g) \to C O (g)

Δ H = - 110 k J

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g)

Δ = 132 k J

Δ H

C (s) + \frac{1}{2} O_{2} (g) ⟶ C O (g); Δ H = - 110 K J

C (s) + H_{2} O (g) ⟶ C O (g) + H_{2} (g); Δ H = 132 K J

Δ H

C (s) + 1 / 2 O_{2} (g) \to C O (g); Δ H = - 110

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g); Δ H = 132

Δ H

C (s) + \frac{1}{2} O_{2} (g) \to C O (g) A H = - 110

C (s) + H_{2} O (g) \to C O (g) + H_{2} (g) Δ H = 132

1273

Join BYJU'S Learning Program