Question

From the following data of $\Delta H$, of the following reactions:

$C\left(s\right)+\frac{1}{2}{O}_2\left(g\right)⟶CO\left(g\right);\Delta H=-110KJ$
$C\left(s\right)+H_{2}O\left(g\right)⟶CO\left(g\right)+H_2\left(g\right);\Delta H=132KJ$

The mole composition of the mixture of steam and oxygen on being passed over coke at 1273 K, keeping the temperature constant is:

• A. $\frac{0.8}{1}$
• B. $\frac{0.6}{1}$
• C. $\frac{0.4}{1}$
• D. $\frac{0.2}{1}$

Answer 1

The correct option is B $\frac{0.6}{1}$

The first reaction is exothermic and the second one is endothermic. If a mixture of steam and $O_2$ is passed over coke and temperature is kept constant, the conversion of each to CO should not show any heat change,

$i.e.,totalheatevolvedinI=totalheatabsorbedinII$.

$n_1\times 2\times 110=n_2\times 132$

$\therefore \frac{n_1}{n_2}=\frac{132}{110\times 2}=\frac{0.6}{1}$