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Byju's Answer
Standard VIII
Chemistry
Combustible and Non-Combustible Substances
From the foll...
Question
From the following data of heats of combustion, find the heat of formation of
C
H
3
O
H
(
l
)
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
→
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
△
r
H
⊖
=
−
726
k
J
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
−
394
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
,
Δ
H
=
−
286
k
J
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Solution
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
→
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
△
r
H
⊖
=
−
726
k
J
.........(i)
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
−
394
k
J
........(ii)
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
,
Δ
H
=
−
286
k
J
...........(iii)
On adding the equation as
(
i
i
)
+
2
×
(
i
i
i
)
we get
C
(
s
)
+
2
H
2
(
g
)
+
2
O
2
(
g
)
→
C
O
2
(
g
)
+
2
H
2
O
(
l
)
⇒
−
394
+
2
×
(
−
286
)
=
−
966
k
J
.........(iv)
Reversing the (i) reaction, we get
C
O
2
(
g
)
+
2
H
2
O
(
l
)
→
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
⇒
+
726
k
J
........(v)
(iv) + (v)
C
(
s
)
+
2
H
2
(
g
)
+
1
2
O
2
(
g
)
→
C
H
3
O
H
(
l
)
⇒
−
966
+
726
=
240
k
J
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0
Similar questions
Q.
From the following data of heats of combustion, find the heat of formation of
C
H
3
O
H
(
l
)
:
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
⟶
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
Δ
H
=
−
726
k
J
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
;
Δ
H
=
−
394
k
J
H
2
(
g
)
+
1
2
O
2
(
g
)
⟶
H
2
O
(
l
)
;
Δ
H
=
−
286
k
J
Q.
Given that,
C
(
s
)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
H
=
−
394
k
J
2
H
2
(
g
)
+
O
2
(
g
)
→
2
H
2
O
(
l
)
;
Δ
H
=
−
568
k
J
C
H
4
(
g
)
+
2
O
2
(
g
)
→
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
Δ
H
=
−
394
k
J
Heat of formation of
C
H
4
is :
Q.
Using the following thermochemical data
C
(
S
)
+
O
2
(
g
)
→
C
O
2
(
g
)
,
Δ
H
=
−
94.0
K
c
a
l
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
,
Δ
H
=
−
68.0
K
c
a
l
C
H
3
C
O
O
H
(
l
)
+
2
O
2
(
g
)
→
2
C
O
2
(
g
)
+
2
H
2
O
(
l
)
,
Δ
H
=
−
210.0
K
c
a
l
The heat of formation of acetic acid is
Q.
Calculate the heat of formation of acetic acid from the following data:
a.
C
(
s
)
+
O
2
(
g
)
⟶
C
O
2
(
g
)
,
Δ
H
=
−
393.7
k
J
b.
H
2
(
g
)
+
1
/
2
O
2
(
g
)
⟶
H
2
O
(
l
)
,
Δ
H
=
−
285.8
k
J
c.
C
H
3
C
O
O
H
(
l
)
+
2
O
2
(
g
)
⟶
2
C
O
2
(
g
)
+
2
H
2
O
(
l
)
,
Δ
H
=
−
873.2
k
J
Q.
Calculate the standard enthalpy of formation of
C
H
3
O
H
(
l
)
from the following data.
C
H
3
O
H
(
l
)
+
3
2
O
2
(
g
)
→
C
O
2
(
g
)
+
2
H
2
O
(
l
)
;
Δ
H
o
=
−
726
kJ
m
o
l
−
1
C(graphite)
+
O
2
(
g
)
→
C
O
2
(
g
)
;
Δ
c
H
0
=
−
393
kJ
m
o
l
−
1
H
2
(
g
)
+
1
2
O
2
(
g
)
→
H
2
O
(
l
)
;
Δ
t
H
o
=
−
286
kJ
m
o
l
−
1
.
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