Question

From the following data of two workers, identify who is a more consistent worker?

	Worker
	A	B
Average Time in completing a job	40	42
Standard Deviation	8	6

Answer 1

$$\begin{gathered} \mathrm{C}.\mathrm{V}.\mathrm{of}\mathrm{worker}\mathrm{A}=\frac{{\sigma }_A}{{\overline{X}}_A}\times 100 \\ =\frac{8}{40}\times 100 \\ =20\% \\ \mathrm{C}.\mathrm{V}.\mathrm{of}\mathrm{worker}\mathrm{B}=\frac{{\sigma }_B}{{\overline{X}}_B}\times 100 \\ =\frac{6}{42}\times 100 \\ =14.29\% \end{gathered}$$

Worker B is more consistent as his C.V. (14.29)% is less than that of C.V of worker A(20%).