From the following figure find the value of $sin 30^{o}$ , $cos 30^{o}$ and $tan 30^{o}$ .

Open in App

Solution

$sin 30^{0} = \frac{P Q}{P R} = \frac{5}{10} = \frac{1}{2}$
$cos 30^{0} = \frac{Q R}{P R} = \frac{5 \sqrt{3}}{10} = \frac{\sqrt{3}}{2}$
$tan 30^{0} = \frac{P Q}{Q R} = \frac{5}{5 \sqrt{3}} = \frac{1}{\sqrt{3}}$

Suggest Corrections

Similar questions

A = (sin 0^{o}, cos 90^{o}), B = (cos 30^{o}, sin 30^{o})

^{'} A^{'}

^{'} B^{'}

sin 30^{o} + cos 30^{o} + tan 45^{o}

\frac{sin 30^{o} + csc 30^{o} + tan 30^{o}}{tan 45^{o} + sec 60^{o}}

60^{o} \times c o s 30^{o} + s i n 60^{o} \times s i n 30^{o}

(s i n 30^{o} = 0.5, c o s 30^{o} = 0.58)

Join BYJU'S Learning Program