From the following information given- determine - Ho for the decomposition of sodium chlorate- NaClO3s- NaCls-3-2O2g - Hof values - NaClO3s-358J-mol- NaCls-410j-mol- O2g-0 kcal-mol

The correct option is B 768 J NaCl O _ 3 ( s ) → NaCl( s ) + 3 2 O _ 2 ( g ) H #176;=∑ n H #176; _ product ∑ n H #176; _ reactants ...

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Byju's Answer

Standard XII

Chemistry

Hess' Law

From the foll...

Question

From the following information given, determine $Δ H^{o}$ for the decomposition of sodium chlorate?
$N a C l O_{3} (s) \to N a C l (s) + \frac{3}{2} O_{2} (g)$
$(Δ H_{f}^{o}$ values $:$ $N a C l O_{3} (s) = 358 J / m o l,$ $N a C l (s) = - 410 j / m o l$ , $O_{2} (g) = 0$ $k c a l / m o l)$

52.0

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- 768

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\frac{3}{2} (- 768 J)

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Solution

The correct option is B $- 768$ J
$N a C l O_{3} (s) \to N a C l (s) + \frac{3}{2} O_{2} (g) △ H ° = \sum n △ {H °}_{p r o d u c t} - \sum n △ {H °}_{r e a c t a n t s} H e r e △ H ° = [\frac{3}{2} (0) + 1 (- 410)] - [1 (358)] = - 410 - 358 = - 768$

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Similar questions

Q. For the decomposition of

1

mole of sodium chlorate, determine

Δ H_{r e a c t i o n}

.
(

Δ H_{f}^{0}

values:

N a C l O_{3} (s) = - 85.7

kcal

/

mol,

N a C l (s) = - 98.2

kcal

/

mol,

O_{2} (g) = 0

kcal

/

mol).

Q. What is

△ H_{t \times n}

for the decomposition of

1 m o l e

N a C l O_{3}

△ H_{f} = - 85.7 k c a l / m o l

for

N a C l O_{3} (s)

and

△ H_{t} = 98.2 k c a l / m o l

for

N a C l (s)

Q. Determine

Δ G^{o}

for the following reaction.

C O (g) + \frac{1}{2} O_{2} (g) \to C O_{2} (g)

;

Δ H^{o} = - 282.84 k J

[Given:

S_{C O_{2}}^{o} = 213.8

^{- 1}

mol

^{- 1}

S^{o}_{C O (g)} = 197.9

J K

^{- 1}

mol

^{- 1}

S^{o}_{O_{2}} = 205.8

J K

^{- 1}

mol

^{- 1}

]

Q. For the dissociation of

P C l_{5} (g)

P C l_{5} (g) ⇌ P C l (g) + C l_{2} (g)

Slope of the linear curve is such that

θ = t a n^{- 1} (- 2.1)

Thus,

△ H^{o}

Q. How many moles of given compound are decomposed in the following decomposition reaction?

N a O C l Δ \to N a C l O_{3} + N a C l

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From the following information given, determine ΔHo for the decomposition of sodium chlorate?NaClO3(s)→NaCl(s)+32O2(g)(ΔHof values : NaClO3(s)=358J/mol, NaCl(s)=−410j/mol, O2(g)=0 kcal/mol)

The correct option is B −768JNaClO3(s)→NaCl(s)+32O2(g)△H°=∑n△H°product−∑n△H°reactantsHere△H°=[32(0)+1(−410)]−[1(358)]=−410−358=−768

From the following information given, determine $Δ H^{o}$ for the decomposition of sodium chlorate?
$N a C l O_{3} (s) \to N a C l (s) + \frac{3}{2} O_{2} (g)$
$(Δ H_{f}^{o}$ values $:$ $N a C l O_{3} (s) = 358 J / m o l,$ $N a C l (s) = - 410 j / m o l$ , $O_{2} (g) = 0$ $k c a l / m o l)$

The correct option is B $- 768$ J
$N a C l O_{3} (s) \to N a C l (s) + \frac{3}{2} O_{2} (g) △ H ° = \sum n △ {H °}_{p r o d u c t} - \sum n △ {H °}_{r e a c t a n t s} H e r e △ H ° = [\frac{3}{2} (0) + 1 (- 410)] - [1 (358)] = - 410 - 358 = - 768$