Question

From the following numbers, choose the numbers that are the cubes of odd numbers:
$125,343,1728,4096,9261$

• A. $125,343,1728,4096$
  
• B. $343,1728,4096,9261$
• C. $125,343,9261$
  
• D. $125,343,4096$

Answer 1

The correct option is C $125,343,9261$

Cube roots of the following numbers are as follows:

$\Rightarrow \sqrt[3]{3125}=\sqrt[3]{35\times 5\times 5}=5\to Itisanoddnumber$

$\Rightarrow \sqrt[3]{3343}=\sqrt[3]{37\times 7\times 7}=7\to Itisanoddnumber$

$\Rightarrow \sqrt[3]{31728}=\sqrt[3]{312\times 12\times 12}=12\to Itisanevennumber$

$\Rightarrow \sqrt[3]{36096}=\sqrt[3]{316\times 16\times 16}=16\to Itisanevennumber$

$\Rightarrow \sqrt[3]{39261}=\sqrt[3]{321\times 21\times 21}=21\to Itisanoddnumber$

Therefore, the numbers that are the cubes of odd numbers are $125,343,9261$.