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Question

# From the following reaction sequence Cl2 + 2KOH → KCl + KClO + H2O 3KClO → 2KCl + KClO3 4KClO3 → 3KClO4+KCl Calculate the mass of chlorine needed to produce 23g of KClO4

A

142g

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B

35.5g

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C

248.5g

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D

215.5g

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Solution

## The correct option is A 142g The given reactions involve certain compounds which are not needed for calculations. ∴ Balance the reaction in a way that the unnecessary compounds get cancelled. 12Cl2 + 24KOH → 12KClO + 12KCl + 12H2O 12KClO → 8KCl + 4KClO3 4KCIO3→ 3KClO4 + KCl 12Cl2 + 24KOH → 3KClO4+ 21KCl + 12H2O We cancel the compounds on either side of the arrow From this final balanced equation 12 moles of Cl2 gives 3 moles of KClO4 12 × (35.5 × 2=71)g = 3 × (138.5)g ∴ 23g of KCIO4=23×12×713×138.5 23g of KClO4 gives≈142g of Cl2 Note: approximate weight of KClO4≈=138

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