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Question

From the following system of unknown vectors (a and b are given vectors)x+y=a,x×y=b,x.a=1 and
x=a+λ(a×b)|a|2. Then λ is

A
1
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B
1
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C
2
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D
2
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Solution

The correct option is A 1
x+y=a(i)x×y=b(ii)x.a=1(iii)
|a|2 x=a+λ(a×b)(iv)
Multiplying equation (i) by dot product of a
x.a+y.a=a.a
1+y.a=|a|2(v)
Now, taking cross product of equation (ii) with a
a×(x×y)=a×b
(a.y)x(a.x)y=a×b
(a.y)x(1)y=a×b From (iii)
(a.y)x(ax)=a×b From (i)
(a.y)x+x=a+a×b
((a.y)+1)x=a+a×b
putting from equation(v)
|a|2x=a+a×b(vi)
Comparing equation (iv),(vi)
λ=1


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