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Question

From the following thermochemical equations:
C2H4C2H6;H=32.7kcal
C6H6+3H2C6H12;H=49.2kcal
Calculate resonance energy of benzene.

A
48.9 kcal
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B
49.2 kcal
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C
16.5 kcal
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D
98.1 kcal
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Solution

The correct option is A 48.9 kcal
Enthalpy of hydrogenation of C=C bond =32.7 kcal
Calculated enthalpy of hydrogenation of benzene =32.7×3=98.1 kcal
Actual enthalpy of hydrogenation of benzene=45.2 kcal
Hence, Resonance energy of benzene=98.1(45.2)=52.9 kcal

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