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Standard XII

Chemistry

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Question

From the given data of equilibrium constants of the following reactions,
$C a O (s) + H_{2} (g) ⇌ C a (s) + H_{2} O (g); K = 60$
$C a O (s) + C O (g) ⇌ C a (s) + C O_{2} (g); K = 400$
Calculate the equilibrium constant of the reaction,
$C O_{2} (g) + H_{2} (g) ⇌ C O (g) + H_{2} O (g)$

0.15

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1.5

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2.5

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0.25

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Solution

The correct option is A 0.15
$C a O (s) + H_{2} (g) ⇌ C a (s) + H_{2} O (g); K_{1} = 60 - (1)$
$C a O (s) + C O (g) ⇌ C a (s) + C O_{2} (g); K = 400 - (2)$
Now substracting the equation (2) from Equation (1), we get
$C O_{2} (g) + H_{2} (g) ⇌ C O (g) + H_{2} O (g); K = ?$
The equilibrium constant (k) can be written as $K = \frac{K_{1}}{K_{2}}$
$= \frac{60}{400} = 0.15$

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Similar questions

Q. From the given data of equilibrium constants of the following reactions,

C a O (s) + H_{2} (g) ⇌ C a (s) + H_{2} O (g); K = 60

C a O (s) + C O (g) ⇌ C a (s) + C O_{2} (g); K = 400

Calculate the equilibrium constant of the reaction,

C O_{2} (g) + H_{2} (g) ⇌ C O (g) + H_{2} O (g)

Q. From the given data of the following reactions;

C a O (s) + H_{2} (g) ⇌ C a (s) + H_{2} O (g)

;

K = 670

C a O (s) + C O (g) ⇌ C a (s) + C O_{2} (g)

;

K = 490

The value of

K_{c}

(nearest integer) for the given reaction is _____.

C O_{2} (g) + H_{2} (g) ⇌ C O (g) + H_{2} O (g)

Calculate the equilibrium constant ( $K_{p}$ ) for the reaction, $C (s) + C O_{2} (g) ⇌ 2 C O (g)$ , at $1300 K$ from the following data:
$C (s) + H_{2} O (g) ⇌ C O (g) + H_{2} (g); K_{p} (1300 K) = 3.9 a t m$

$H_{2} (g) + C O_{2} (g) ⇌ C O (g) + H_{2} O (g); K_{p} (1300 K) = 0.623 a t m$

Q. The equilibrium constants for the following reaction at 1000 K are given :

C o O (s) + H_{2 (g)} ⇌ C o (s) + H_{2} O_{(g)} K_{1} = 62.5

C o O (s) + C O_{(g)} ⇌ C o (s) + C O_{2 (g)} K_{2} = 500

Then the equilibrium constant [K] for the below given reaction is :

C O_{(g)} + H_{2} O_{(g)} ⇌ C O_{2 (g)} + H_{2 (g)}

Q. The equilibrium constant of the equation,

H_{2} O (g) + C O (g) ⇌ H_{2} (g) + C O_{2} (g)

0.44

1259 K

. The value of equilibrium constant of the equation,

H_{2} (g) + C O_{2} (g) ⇌ H_{2} O (g) + C O (g)

will be:

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From the given data of equilibrium constants of the following reactions, CaO(s)+H2(g)⇌Ca(s)+H2O(g);K=60 CaO(s)+CO(g)⇌Ca(s)+CO2(g);K=400 Calculate the equilibrium constant of the reaction, CO2(g)+H2(g)⇌CO(g)+H2O(g)

The correct option is A 0.15CaO(s)+H2(g)⇌Ca(s)+H2O(g);K1=60−(1) CaO(s)+CO(g)⇌Ca(s)+CO2(g);K=400−(2) Now substracting the equation (2) from Equation (1), we get CO2(g)+H2(g)⇌CO(g)+H2O(g);K=? The equilibrium constant (k) can be written as K=K1K2 =60400=0.15

From the given data of equilibrium constants of the following reactions,
$C a O (s) + H_{2} (g) ⇌ C a (s) + H_{2} O (g); K = 60$
$C a O (s) + C O (g) ⇌ C a (s) + C O_{2} (g); K = 400$
Calculate the equilibrium constant of the reaction,
$C O_{2} (g) + H_{2} (g) ⇌ C O (g) + H_{2} O (g)$