Question

From the given diagram, in which ABCD is a parallelogram, ABL is a line segment and E is mid point of BC.

Hence, AL = 2DC

If the above statement is true then mention answer as 1, else mention 0 if false

Answer 1

Given, ABCD is a parallelogram. E is mid point of BC.

Now, In $△CED$ and $△BEL$

$\angle CED=\angle BEL$(Vertically opposite angles)

$EC=BE$ (Given, E is mid point of BC)

$\angle DCE=\angle EBL$ (Alternate angles)

Thus, $△CED\cong △BEL$ (SAS rule)

Hence, $CD=BL$ (By cpct)

Since, $CD=AB$ (ABCD is a parallelogram)

Thus, $CD=BL=AB$
Now, $AL=AB+BL$

$AL=AB+AB$

$AL=2AB=2CD$