Question

From the given figure, find $\angle ADB$ .

Answer 1

In cyclic quadrilateral opposite angles are equal

$⟹\angle A=\angle C={100}^{\circ }$

In $\Delta ABD$

Sum of all angles is ${180}^{\circ }$

$\angle A+\angle B+\angle D=180\angle D=180-100-70\angle D={10}^{\circ }$