wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

From the given figure, find P. [2 MARKS]


Open in App
Solution

Concept: 1 Mark
Application: 1 Mark

In ΔABC and ΔPQR,

ABRQ=3.87.6=12

BCQP=612=12

and CAPR=12

ABRQ=BCQP=CAPR

So, ΔABCΔRQP [SSS similarity]

C=P [Corresponding angles of similar triangles]

But C=180AB [Angle sum property]

C=1808060=40

So, P=40


flag
Suggest Corrections
thumbs-up
8
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Criteria for Congruency
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon