Question

From the given figure, find the value of m if, cosec C is $1\frac{2}{m}$, m is

Answer 1

Given: $\angle B={90}^{\circ }$, $AB=3$ and $BC=4$

In $△ABC$,

$A{B}^2+B{C}^2=A{C}^2$

$3^2+4^2=A{C}^2$

$A{C}^2=25$

$AC=5$ cm

$cosecC=\frac{AC}{AB}=\frac{5}{3}=1\frac{2}{3}$

$cosecC=1\frac{2}{m}$

$\therefore m=3$