Question

From the given figure, what is the angular velocity of rod of length L = 1 m?
Where velocity of end A is 10 m/s and angle's are given as shown below,

• A. 15 rad/s
• B. 10.5 rad/s
• C. 14 rad/s
• D. 12.5 rad/s

Answer 1

The correct option is D 12.5 rad/s

$\Rightarrow 10sin37=V_{B}sin53$

$10\times \frac{3}{5}=V_B\times \frac{4}{5}$

$V_B=\frac{30}{4}=\frac{15}{2}$ m/s

W=$\frac{(V_A+V_B)\perp }{L}=\frac{10cos37+V_{B}cos53}{L}$

W=$10\times \frac{4}{5}+\frac{15}{2}\times \frac{3}{5}=8+\frac{9}{2}$

W=$12.5$ rad/s