From the given set of compounds, the number of fluorinating agents is/are:
$S b F_{3}, S F_{6}, T e f l o n, F_{2}, F l u o r a p a t i t e, C l F_{3}, F l u o r s p a r, A s F_{3}, X e F_{2}$

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Solution

The typical minerals like Fluorapatite and fluorite (fluorspar) are definitely not fluorinating agents. At best – they are a source of fluoride ions or hydrogen fluoride. Also, the minerals generally contain impurities. Further, Teflon is a polymer of tetrafluoroethene; the polymer is very unreactive in general.

$S F_{6}$ doesn’t undergo hydrolysis easily and is not considered a fluorinating agent. It is pretty much inert and non-flammable! This is because of its geometry:

The rest are all well-known fluorinating agents.

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From the given set of compounds, the number of fluorinating agents is/are:
$S b F_{3}, S F_{6}, T e f l o n, F_{2}, F l u o r a p a t i t e, C l F_{3}, F l u o r s p a r, A s F_{3}, X e F_{2}$

S F_{4}, B F_{4}^{-}, C l F_{3}, A s F_{3}, P C l_{5}, B r F_{5}, X e F_{4}, S F_{6}

The number of species that have two lone pairs of electrons in their central atom is/are

{C l F}_{3}

is a............ in the reaction

C I F_{3} + A s F_{3} ⟶ [C l F_{2}]^{+} [A s F_{4}]^{-}

and is a ................ in the reaction

C l F_{3} + N O F . . . \to [N O]^{+} [C l F_{4}]^{-}

Q. Find the number of molecule(s) is/are having zero dipole moment and linear shape from the following:

C l F_{3}, I_{3}^{-}, C O_{2}, H g C l_{2}, I C l_{2}^{-}, X e F_{2}

Q. How many of the following compounds are planar, as well as non polar compound:

C_{3} O_{2}, C H_{2} = C = C H_{2}, B F_{3}, C C l_{4}, S F_{6}, X e F_{4}, I F_{4}^{-}, I F_{7}, S F_{4}, C l F_{3}

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From the given set of compounds, the number of fluorinating agents is/are: SbF3,SF6,Teflon,F2,Fluorapatite,ClF3,Fluorspar,AsF3,XeF2

From the given set of compounds, the number of fluorinating agents is/are:
$S b F_{3}, S F_{6}, T e f l o n, F_{2}, F l u o r a p a t i t e, C l F_{3}, F l u o r s p a r, A s F_{3}, X e F_{2}$