From the graph the value of $O A =$ ...................

0

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a^{2} + b^{2}

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\sqrt{a^{2} + b^{2}}

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\sqrt{a + b}

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Solution

The correct option is C $\sqrt{a^{2} + b^{2}}$
Draw a perpendicular from point $A$ on $X -$ axis meeting at point $M$ .
So, $A M = b$ and $O M = a$
Using Pythagoras Theorem we can conclude,
$O A^{2} = O M^{2} + A M^{2}$
$⟹ O A^{2} = a^{2} + b^{2}$
$⟹ O A = \sqrt{a^{2} + b^{2}}$
Hence, option C is correct.

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