From the heats of reaction of these individual reactions- A - B - 2C H - -500 kJ D - 2B - E H - -700 kJ 2D - 2A - F H - -50 kJFind the heat of reaction for F - 6B - 2E - 4C

The correct option is E 2450 kJ 2D + 2A → F #160; H = +50 kJ Reverse above equation F → 2D + 2A #160; #160; H = 50 kJ #160; .... ...

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Byju's Answer

Standard XII

Chemistry

Hess' Law

From the heat...

Question

From the heats of reaction of these individual reactions:
$A + B \to 2 C$ $△ H = - 500 k J$
$D + 2 B \to E$ $△ H = - 700 k J$
$2 D + 2 A \to F$ $△ H = + 50 k J$
Find the heat of reaction for $F + 6 B$
$\to 2 E + 4 C$

+450 kJ

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-1100 kJ

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+2350 kJ

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-350 kJ

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-2450 kJ

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Solution

The correct option is E -2450 kJ
$2 D + 2 A \to F$ $△ H = + 50 k J$
Reverse above equation
$F \to 2 D + 2 A$ $△ H = - 50 k J$ ......(1)
$D + 2 B \to E$ $△ H = - 700 k J$
Multiply above equation with (2)
$2 D + 4 B \to 2 E$ $△ H = - 1400 k J$ ......(2)
$A + B \to 2 C$ $△ H = - 500 k J$
Multiply above equation with (2)
$2 A + 2 B \to 4 C$ $△ H = - 1000 k J$ ......(3)
Add equations (1), (2) and (3)
$F + 6 B \to 2 E + 4 C$ $△ H = - 50 k J - 1400 k J - 1000 k J = - 2450 k J$

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From the heats of reaction of these individual reactions:A+B→2C △H=−500kJD+2B→E △H=−700kJ2D+2A→F △H=+50kJFind the heat of reaction for F+6B→2E+4C

From the heats of reaction of these individual reactions:
$A + B \to 2 C$ $△ H = - 500 k J$
$D + 2 B \to E$ $△ H = - 700 k J$
$2 D + 2 A \to F$ $△ H = + 50 k J$
Find the heat of reaction for $F + 6 B$
$\to 2 E + 4 C$