We have, d(D,E)=5,d(E,F)=8,d(D,F)=6d(D,E)=5,d(E,F)=8,d(D,F)=6
Now, 5+8=135+8=13, so 5+8≠65+8≠6; 8+6=148+6=14, so 8+6≠58+6≠5 and 5+6=115+6=11, so 5+6≠85+6≠8
Since the sum of the distances between two pairs of points is not equal to the distance between the third pair of points, so the given points D, E, and F are non-collinear.