Question

From the options, choose the irrational number that lie between 3 & 4.

• A. $\sqrt{9}$
• B. $\sqrt{13}$
• C. $\sqrt{19}$
• D. $\sqrt{16}$

Answer 1

The correct option is B $\sqrt{13}$

$3\times 3$ = 9, a perfect square , hence $\sqrt{9}$ won’t be irrational .
Also 16 is the perfect square of 4, hence $\sqrt{16}$ is rational

$3^2=9$ & $4^2=16$, hence all the numbers between $\sqrt{9}$ & $\sqrt{16}$ lie between 3 & 4.

We can see that $\sqrt{13}$ is the irrational number between $\sqrt{9}$ & $\sqrt{16}$, and they lie between 3 and 4.