wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

From the origin chords are drawn to the circle (x−1)2+y2=1. The equation of the locus of the middle points of these chords is


A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C


The given circle is x2+y2−2x=0. Let (x1,y1) be the middle point of any chord of this circle, than its equation is S1=T.

or x21+y21−2x1=xx1+yy1−(x+x1)

If it passes through (0,0), then

x21+y21−2x1=−x1⇒x21+y21−x1=0

Hence the required locus of the given point (x1,y1) is x2+y2−x=0


flag
Suggest Corrections
thumbs-up
22
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Chords and Pair of Tangents
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon